What is the total resistance in a series circuit containing resistors 2 Ω, 3 Ω, and 5 Ω?

• A. 6 Ω
• B. 2 Ω
• C. 10 Ω
• D. 5 Ω

Answer: (C)

In a series circuit, the total resistance is the sum of all the individual resistances. The same current flows through each resistor, so each resistor adds to the overall opposition to the current. For resistors of 2 Ω, 3 Ω and 5 Ω in series, the total resistance is 2 + 3 + 5 = 10 Ω. This makes sense because you’re combining all three resistances along the path, increasing the total opposition. The other numbers don’t reflect the sum of all three (2 Ω or 5 Ω would be just one resistor, and 6 Ω isn’t obtainable from 2, 3, and 5 in series since 2+3=5, 2+5=7, and 3+5=8).