Power in a branch with I = 6 A and R = 2 Ω is

Study for the IGCSE Physics Electricity Test. Master key concepts with flashcards and multiple choice questions, each providing hints and explanations. Prepare with confidence for your exam!

Multiple Choice

Power in a branch with I = 6 A and R = 2 Ω is

Explanation:
Power in a resistor is given by P = I^2R. With I = 6 A and R = 2 Ω, P = (6)^2 × 2 = 36 × 2 = 72 W. You can also find the voltage first: V = IR = 6 × 2 = 12 V, then P = VI = 12 × 6 = 72 W. Both approaches give 72 watts, so that is the power in the branch.

Power in a resistor is given by P = I^2R. With I = 6 A and R = 2 Ω, P = (6)^2 × 2 = 36 × 2 = 72 W. You can also find the voltage first: V = IR = 6 × 2 = 12 V, then P = VI = 12 × 6 = 72 W. Both approaches give 72 watts, so that is the power in the branch.

Subscribe

Get the latest from Passetra

You can unsubscribe at any time. Read our privacy policy