In a parallel arrangement of a 6 Ω resistor across a 12 V supply, what is the current through the 6 Ω resistor?

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Multiple Choice

In a parallel arrangement of a 6 Ω resistor across a 12 V supply, what is the current through the 6 Ω resistor?

Explanation:
When a resistor is connected across a constant voltage, the current through it follows Ohm’s law: I = V/R. In a parallel arrangement, each branch has the full supply voltage across it, so the 6 Ω resistor has 12 V across it. The current through that resistor is 12 V divided by 6 Ω, which equals 2 A. So this branch draws 2 amperes from the supply. If there were other parallel branches, they would draw their own currents and the total current from the supply would be the sum of all branches.

When a resistor is connected across a constant voltage, the current through it follows Ohm’s law: I = V/R. In a parallel arrangement, each branch has the full supply voltage across it, so the 6 Ω resistor has 12 V across it. The current through that resistor is 12 V divided by 6 Ω, which equals 2 A. So this branch draws 2 amperes from the supply. If there were other parallel branches, they would draw their own currents and the total current from the supply would be the sum of all branches.

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